efficient way to solve X*A=B
Hallo,
for me it seems to be too complicated to solve X*A=B, like A'*X'=B' with DTRTRS. Moreover A is triangular and with B are parts of one matrix. How to solve this "standardized" problem efficient?
for me it seems to be too complicated to solve X*A=B, like A'*X'=B' with DTRTRS. Moreover A is triangular and with B are parts of one matrix. How to solve this "standardized" problem efficient?